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x-50=5(2x+3)-11
We move all terms to the left:
x-50-(5(2x+3)-11)=0
We calculate terms in parentheses: -(5(2x+3)-11), so:We get rid of parentheses
5(2x+3)-11
We multiply parentheses
10x+15-11
We add all the numbers together, and all the variables
10x+4
Back to the equation:
-(10x+4)
x-10x-4-50=0
We add all the numbers together, and all the variables
-9x-54=0
We move all terms containing x to the left, all other terms to the right
-9x=54
x=54/-9
x=-6
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