5(2+x)=2x-2(-x-2)

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Solution for 5(2+x)=2x-2(-x-2) equation:



5(2+x)=2x-2(-x-2)
We move all terms to the left:
5(2+x)-(2x-2(-x-2))=0
We add all the numbers together, and all the variables
5(x+2)-(2x-2(-1x-2))=0
We multiply parentheses
5x-(2x-2(-1x-2))+10=0
We calculate terms in parentheses: -(2x-2(-1x-2)), so:
2x-2(-1x-2)
We multiply parentheses
2x+2x+4
We add all the numbers together, and all the variables
4x+4
Back to the equation:
-(4x+4)
We get rid of parentheses
5x-4x-4+10=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6

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