4(u-4)+3u=5

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Solution for 4(u-4)+3u=5 equation: 



4(u-4)+3u=5

We move all terms to the left:

4(u-4)+3u-(5)=0

We add all the numbers together, and all the variables

3u+4(u-4)-5=0

We multiply parentheses

3u+4u-16-5=0

We add all the numbers together, and all the variables

7u-21=0

We move all terms containing u to the left, all other terms to the right

7u=21

u=21/7

u=3

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