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x-3=1/x+3
We move all terms to the left:
x-3-(1/x+3)=0
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
x-1/x-3-3=0
We multiply all the terms by the denominator
x*x-3*x-3*x-1=0
We add all the numbers together, and all the variables
-6x+x*x-1=0
Wy multiply elements
x^2-6x-1=0
a = 1; b = -6; c = -1;
Δ = b2-4ac
Δ = -62-4·1·(-1)
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{10}}{2*1}=\frac{6-2\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{10}}{2*1}=\frac{6+2\sqrt{10}}{2} $
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