6(t-1)-2(2t+3)=5(t+3)

Solution for 6(t-1)-2(2t+3)=5(t+3) equation:

6(t-1)-2(2t+3)=5(t+3)

We move all terms to the left:

6(t-1)-2(2t+3)-(5(t+3))=0

We multiply parentheses

6t-4t-(5(t+3))-6-6=0


We calculate terms in parentheses: -(5(t+3)), so:

5(t+3)

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)


We add all the numbers together, and all the variables

2t-(5t+15)-12=0

We get rid of parentheses

2t-5t-15-12=0

We add all the numbers together, and all the variables

-3t-27=0

We move all terms containing t to the left, all other terms to the right

-3t=27

t=27/-3

t=-9