14(2t-3)-2(t-2)=10(3t-4)

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Solution for 14(2t-3)-2(t-2)=10(3t-4) equation: 



14(2t-3)-2(t-2)=10(3t-4)

We move all terms to the left:

14(2t-3)-2(t-2)-(10(3t-4))=0

We multiply parentheses

28t-2t-(10(3t-4))-42+4=0



We calculate terms in parentheses: -(10(3t-4)), so:

10(3t-4)

We multiply parentheses

30t-40

Back to the equation:

-(30t-40)



We add all the numbers together, and all the variables

26t-(30t-40)-38=0

We get rid of parentheses

26t-30t+40-38=0

We add all the numbers together, and all the variables

-4t+2=0

We move all terms containing t to the left, all other terms to the right

-4t=-2

t=-2/-4

t=1/2

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