x-(2x-1)/3=(x-1)/5

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Solution for x-(2x-1)/3=(x-1)/5 equation: 



x-(2x-1)/3=(x-1)/5

We move all terms to the left:

x-(2x-1)/3-((x-1)/5)=0

We calculate fractions


x+(-2x)/()+(-((x-1)*3)/()=0



We calculate terms in parentheses: +(-((x-1)*3)/(), so:

-((x-1)*3)/(

We multiply all the terms by the denominator


-((x-1)*3)



We calculate terms in parentheses: -((x-1)*3), so:

(x-1)*3

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

-3x+3

Back to the equation:

+(-3x+3)



We get rid of parentheses

x+(-2x)/()-3x+3=0

We multiply all the terms by the denominator


x*()+(-2x)-3x*()+3*()=0

We add all the numbers together, and all the variables

x*()+(-2x)-3x*()=0

We get rid of parentheses

x*()-2x-3x*()=0

We add all the numbers together, and all the variables

-2x+x*()-3x*()=0

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