F=9/5(k)-273.15)+32

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Solution for F=9/5(k)-273.15)+32 equation:



=9/5(F)-273.15)+32
We move all terms to the left:
-(9/5(F)-273.15)+32)=0
Domain of the equation: 5F-273.15)!=0
F∈R
We add all the numbers together, and all the variables
-(9/5F-273.15)=0
We get rid of parentheses
-9/5F+273.15=0
We multiply all the terms by the denominator
(273.15)*5F-9=0
We multiply parentheses
1365.75F-9=0
We move all terms containing F to the left, all other terms to the right
1365.75F=9
F=9/1365.75
F=3/455.25

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