X2+112x+4=0

Solution for X2+112x+4=0 equation:

X2+112X+4=0

We add all the numbers together, and all the variables

X^2+112X+4=0

a = 1; b = 112; c = +4;
Δ = b2-4ac
Δ = 1122-4·1·4
Δ = 12528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12528}=\sqrt{144*87}=\sqrt{144}*\sqrt{87}=12\sqrt{87}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-12\sqrt{87}}{2*1}=\frac{-112-12\sqrt{87}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+12\sqrt{87}}{2*1}=\frac{-112+12\sqrt{87}}{2}
$