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x+8=9/5x
We move all terms to the left:
x+8-(9/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+9/5x)+8=0
We get rid of parentheses
x-9/5x+8=0
We multiply all the terms by the denominator
x*5x+8*5x-9=0
Wy multiply elements
5x^2+40x-9=0
a = 5; b = 40; c = -9;
Δ = b2-4ac
Δ = 402-4·5·(-9)
Δ = 1780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1780}=\sqrt{4*445}=\sqrt{4}*\sqrt{445}=2\sqrt{445}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{445}}{2*5}=\frac{-40-2\sqrt{445}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{445}}{2*5}=\frac{-40+2\sqrt{445}}{10} $
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