(16+2x)(22+2x)=952

Solution for (16+2x)(22+2x)=952 equation:

(16+2x)(22+2x)=952

We move all terms to the left:

(16+2x)(22+2x)-(952)=0

We add all the numbers together, and all the variables

(2x+16)(2x+22)-952=0

We multiply parentheses ..

(+4x^2+44x+32x+352)-952=0

We get rid of parentheses

4x^2+44x+32x+352-952=0

We add all the numbers together, and all the variables

4x^2+76x-600=0

a = 4; b = 76; c = -600;
Δ = b2-4ac
Δ = 762-4·4·(-600)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15376}=124$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-124}{2*4}=\frac{-200}{8}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+124}{2*4}=\frac{48}{8}
=6
$