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5(2p+1)=+3(3p-1)
We move all terms to the left:
5(2p+1)-(+3(3p-1))=0
We multiply parentheses
10p-(+3(3p-1))+5=0
We calculate terms in parentheses: -(+3(3p-1)), so:We get rid of parentheses
+3(3p-1)
determiningTheFunctionDomain 3(3p-1)
We multiply parentheses
9p-3
Back to the equation:
-(9p-3)
10p-9p+3+5=0
We add all the numbers together, and all the variables
p+8=0
We move all terms containing p to the left, all other terms to the right
p=-8
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