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x+3x(5-x)=11
We move all terms to the left:
x+3x(5-x)-(11)=0
We add all the numbers together, and all the variables
x+3x(-1x+5)-11=0
We multiply parentheses
-3x^2+x+15x-11=0
We add all the numbers together, and all the variables
-3x^2+16x-11=0
a = -3; b = 16; c = -11;
Δ = b2-4ac
Δ = 162-4·(-3)·(-11)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{31}}{2*-3}=\frac{-16-2\sqrt{31}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{31}}{2*-3}=\frac{-16+2\sqrt{31}}{-6} $
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