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2(3/2x-5)+x-2=2
We move all terms to the left:
2(3/2x-5)+x-2-(2)=0
Domain of the equation: 2x-5)!=0We add all the numbers together, and all the variables
x∈R
x+2(3/2x-5)-4=0
We multiply parentheses
x+6x-10-4=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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