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256x^2-676=4
We move all terms to the left:
256x^2-676-(4)=0
We add all the numbers together, and all the variables
256x^2-680=0
a = 256; b = 0; c = -680;
Δ = b2-4ac
Δ = 02-4·256·(-680)
Δ = 696320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{696320}=\sqrt{4096*170}=\sqrt{4096}*\sqrt{170}=64\sqrt{170}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{170}}{2*256}=\frac{0-64\sqrt{170}}{512} =-\frac{64\sqrt{170}}{512} =-\frac{\sqrt{170}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{170}}{2*256}=\frac{0+64\sqrt{170}}{512} =\frac{64\sqrt{170}}{512} =\frac{\sqrt{170}}{8} $
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