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(2x-9+x-3)/2=x
We move all terms to the left:
(2x-9+x-3)/2-(x)=0
We add all the numbers together, and all the variables
(3x-12)/2-x=0
We add all the numbers together, and all the variables
-1x+(3x-12)/2=0
We multiply all the terms by the denominator
-1x*2+(3x-12)=0
Wy multiply elements
-2x+(3x-12)=0
We get rid of parentheses
-2x+3x-12=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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