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x+3/x=160
We move all terms to the left:
x+3/x-(160)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
x*x-160*x+3=0
We add all the numbers together, and all the variables
-160x+x*x+3=0
Wy multiply elements
x^2-160x+3=0
a = 1; b = -160; c = +3;
Δ = b2-4ac
Δ = -1602-4·1·3
Δ = 25588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25588}=\sqrt{4*6397}=\sqrt{4}*\sqrt{6397}=2\sqrt{6397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{6397}}{2*1}=\frac{160-2\sqrt{6397}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{6397}}{2*1}=\frac{160+2\sqrt{6397}}{2} $
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