X+(12/100)x=142

Solution for X+(12/100)x=142 equation:

X+(12/100)X=142

We move all terms to the left:

X+(12/100)X-(142)=0


Domain of the equation: 100)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+12/100)X-142=0

We multiply parentheses

12X^2+X-142=0

a = 12; b = 1; c = -142;
Δ = b2-4ac
Δ = 12-4·12·(-142)
Δ = 6817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{6817}}{2*12}=\frac{-1-\sqrt{6817}}{24}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{6817}}{2*12}=\frac{-1+\sqrt{6817}}{24}
$