X+(12/100*x)=142

Solution for X+(12/100*x)=142 equation:

X+(12/100X)=142

We move all terms to the left:

X+(12/100X)-(142)=0


Domain of the equation: 100X)!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

X+(+12/100X)-142=0

We get rid of parentheses

X+12/100X-142=0

We multiply all the terms by the denominator


X*100X-142*100X+12=0

Wy multiply elements

100X^2-14200X+12=0

a = 100; b = -14200; c = +12;
Δ = b2-4ac
Δ = -142002-4·100·12
Δ = 201635200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{201635200}=\sqrt{1600*126022}=\sqrt{1600}*\sqrt{126022}=40\sqrt{126022}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14200)-40\sqrt{126022}}{2*100}=\frac{14200-40\sqrt{126022}}{200}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14200)+40\sqrt{126022}}{2*100}=\frac{14200+40\sqrt{126022}}{200}
$