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x+12=10/3(x-6)
We move all terms to the left:
x+12-(10/3(x-6))=0
Domain of the equation: 3(x-6))!=0We multiply all the terms by the denominator
x∈R
x*3(x-6))-(10+12*3(x-6))=0
Wy multiply elements
3x^2(x+36x(x=0
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