(5+y)(5y-2)=0

Solution for (5+y)(5y-2)=0 equation:

(5+y)(5y-2)=0

We add all the numbers together, and all the variables

(y+5)(5y-2)=0

We multiply parentheses ..

(+5y^2-2y+25y-10)=0

We get rid of parentheses

5y^2-2y+25y-10=0

We add all the numbers together, and all the variables

5y^2+23y-10=0

a = 5; b = 23; c = -10;
Δ = b2-4ac
Δ = 232-4·5·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-27}{2*5}=\frac{-50}{10}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+27}{2*5}=\frac{4}{10}
=2/5
$