2(2y-5)-15=4(6y-4)+23

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Solution for 2(2y-5)-15=4(6y-4)+23 equation: 



2(2y-5)-15=4(6y-4)+23

We move all terms to the left:

2(2y-5)-15-(4(6y-4)+23)=0

We multiply parentheses

4y-(4(6y-4)+23)-10-15=0



We calculate terms in parentheses: -(4(6y-4)+23), so:

4(6y-4)+23

We multiply parentheses

24y-16+23

We add all the numbers together, and all the variables

24y+7

Back to the equation:

-(24y+7)



We add all the numbers together, and all the variables

4y-(24y+7)-25=0

We get rid of parentheses

4y-24y-7-25=0

We add all the numbers together, and all the variables

-20y-32=0

We move all terms containing y to the left, all other terms to the right

-20y=32

y=32/-20

y=-1+3/5

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