x(x+10)=10(-10-x)

Solution for x(x+10)=10(-10-x) equation:

x(x+10)=10(-10-x)

We move all terms to the left:

x(x+10)-(10(-10-x))=0

We add all the numbers together, and all the variables

x(x+10)-(10(-1x-10))=0

We multiply parentheses

x^2+10x-(10(-1x-10))=0


We calculate terms in parentheses: -(10(-1x-10)), so:

10(-1x-10)

We multiply parentheses

-10x-100

Back to the equation:

-(-10x-100)


We get rid of parentheses

x^2+10x+10x+100=0

We add all the numbers together, and all the variables

x^2+20x+100=0

a = 1; b = 20; c = +100;
Δ = b2-4ac
Δ = 202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{2}=-10$