2y=7(3y+5)+12

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Solution for 2y=7(3y+5)+12 equation: 



2y=7(3y+5)+12

We move all terms to the left:

2y-(7(3y+5)+12)=0



We calculate terms in parentheses: -(7(3y+5)+12), so:

7(3y+5)+12

We multiply parentheses

21y+35+12

We add all the numbers together, and all the variables

21y+47

Back to the equation:

-(21y+47)



We get rid of parentheses

2y-21y-47=0

We add all the numbers together, and all the variables

-19y-47=0

We move all terms containing y to the left, all other terms to the right

-19y=47

y=47/-19

y=-2+9/19

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