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(x+0.7)(x+1.7)=0
We multiply parentheses ..
(+x^2+1.7x+0.7x+1.19)=0
We get rid of parentheses
x^2+1.7x+0.7x+1.19=0
We add all the numbers together, and all the variables
x^2+2.4x+1.19=0
a = 1; b = 2.4; c = +1.19;
Δ = b2-4ac
Δ = 2.42-4·1·1.19
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-1}{2*1}=\frac{-3.4}{2} =-1+1/1.42857142857 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+1}{2*1}=\frac{-1.4}{2} =-1/1.42857142857 $
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