2y=-7(3y+5)+12

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Solution for 2y=-7(3y+5)+12 equation: 



2y=-7(3y+5)+12

We move all terms to the left:

2y-(-7(3y+5)+12)=0



We calculate terms in parentheses: -(-7(3y+5)+12), so:

-7(3y+5)+12

We multiply parentheses

-21y-35+12

We add all the numbers together, and all the variables

-21y-23

Back to the equation:

-(-21y-23)



We get rid of parentheses

2y+21y+23=0

We add all the numbers together, and all the variables

23y+23=0

We move all terms containing y to the left, all other terms to the right

23y=-23

y=-23/23

y=-1

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