x(x)+4=(x+1)(x+3)

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Solution for x(x)+4=(x+1)(x+3) equation: 



x(x)+4=(x+1)(x+3)

We move all terms to the left:

x(x)+4-((x+1)(x+3))=0

We multiply parentheses ..

-((+x^2+3x+x+3))+xx+4=0



We calculate terms in parentheses: -((+x^2+3x+x+3)), so:

(+x^2+3x+x+3)

We get rid of parentheses

x^2+3x+x+3

We add all the numbers together, and all the variables

x^2+4x+3

Back to the equation:

-(x^2+4x+3)



We get rid of parentheses

-x^2-4x+xx-3+4=0

We add all the numbers together, and all the variables

-1x^2-4x+xx+1=0

We move all terms containing x to the left, all other terms to the right

-1x^2-4x+xx=-1

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