3(y+9)=12y+133(y+9)=12y+133

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Solution for 3(y+9)=12y+133(y+9)=12y+133 equation:



3(y+9)=12y+133(y+9)=12y+133
We move all terms to the left:
3(y+9)-(12y+133(y+9))=0
We multiply parentheses
3y-(12y+133(y+9))+27=0
We calculate terms in parentheses: -(12y+133(y+9)), so:
12y+133(y+9)
We multiply parentheses
12y+133y+1197
We add all the numbers together, and all the variables
145y+1197
Back to the equation:
-(145y+1197)
We get rid of parentheses
3y-145y-1197+27=0
We add all the numbers together, and all the variables
-142y-1170=0
We move all terms containing y to the left, all other terms to the right
-142y=1170
y=1170/-142
y=-8+17/71

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