7(y-4)=(3y+4)-36

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Solution for 7(y-4)=(3y+4)-36 equation: 



7(y-4)=(3y+4)-36

We move all terms to the left:

7(y-4)-((3y+4)-36)=0

We multiply parentheses

7y-((3y+4)-36)-28=0



We calculate terms in parentheses: -((3y+4)-36), so:

(3y+4)-36

We get rid of parentheses

3y+4-36

We add all the numbers together, and all the variables

3y-32

Back to the equation:

-(3y-32)



We get rid of parentheses

7y-3y+32-28=0

We add all the numbers together, and all the variables

4y+4=0

We move all terms containing y to the left, all other terms to the right

4y=-4

y=-4/4

y=-1

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