x(3x-3)=(3x+9)(x-1)

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Solution for x(3x-3)=(3x+9)(x-1) equation: 



x(3x-3)=(3x+9)(x-1)

We move all terms to the left:

x(3x-3)-((3x+9)(x-1))=0

We multiply parentheses

3x^2-3x-((3x+9)(x-1))=0

We multiply parentheses ..

3x^2-((+3x^2-3x+9x-9))-3x=0



We calculate terms in parentheses: -((+3x^2-3x+9x-9)), so:

(+3x^2-3x+9x-9)

We get rid of parentheses

3x^2-3x+9x-9

We add all the numbers together, and all the variables

3x^2+6x-9

Back to the equation:

-(3x^2+6x-9)



We add all the numbers together, and all the variables

3x^2-3x-(3x^2+6x-9)=0

We get rid of parentheses

3x^2-3x^2-3x-6x+9=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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