X-40+1/2x+20+2x-115=180

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Solution for X-40+1/2x+20+2x-115=180 equation: 



X-40+1/2X+20+2X-115=180

We move all terms to the left:

X-40+1/2X+20+2X-115-(180)=0



Domain of the equation: 2X!=0

X!=0/2

X!=0

X∈R



We add all the numbers together, and all the variables

3X+1/2X-315=0

We multiply all the terms by the denominator


3X*2X-315*2X+1=0

Wy multiply elements

6X^2-630X+1=0

a = 6; b = -630; c = +1;
Δ = b2-4ac
Δ = -6302-4·6·1
Δ = 396876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:


$\sqrt{\Delta}=\sqrt{396876}=\sqrt{4*99219}=\sqrt{4}*\sqrt{99219}=2\sqrt{99219}$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-630)-2\sqrt{99219}}{2*6}=\frac{630-2\sqrt{99219}}{12}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-630)+2\sqrt{99219}}{2*6}=\frac{630+2\sqrt{99219}}{12}
$

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