-4(b=1)+2b=3(2b-1)

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Solution for -4(b=1)+2b=3(2b-1) equation: 



-4(b=1)+2b=3(2b-1)

We move all terms to the left:

-4(b-(1)+2b)=0

We add all the numbers together, and all the variables

-4(3b-1)=0

We multiply parentheses

-12b+4=0

We move all terms containing b to the left, all other terms to the right

-12b=-4

b=-4/-12

b=1/3

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