x(2x-4)=(2x+4)(x-8)

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Solution for x(2x-4)=(2x+4)(x-8) equation: 



x(2x-4)=(2x+4)(x-8)

We move all terms to the left:

x(2x-4)-((2x+4)(x-8))=0

We multiply parentheses

2x^2-4x-((2x+4)(x-8))=0

We multiply parentheses ..

2x^2-((+2x^2-16x+4x-32))-4x=0



We calculate terms in parentheses: -((+2x^2-16x+4x-32)), so:

(+2x^2-16x+4x-32)

We get rid of parentheses

2x^2-16x+4x-32

We add all the numbers together, and all the variables

2x^2-12x-32

Back to the equation:

-(2x^2-12x-32)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-12x-32)=0

We get rid of parentheses

2x^2-2x^2-4x+12x+32=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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