(9/y)+(3/y)=2

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Solution for (9/y)+(3/y)=2 equation: 



(9/y)+(3/y)=2

We move all terms to the left:

(9/y)+(3/y)-(2)=0



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+9/y)+(+3/y)-2=0

We get rid of parentheses

9/y+3/y-2=0

We multiply all the terms by the denominator


-2*y+9+3=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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