(2x+1)*(x+5)=5

Solution for (2x+1)*(x+5)=5 equation:

(2x+1)(x+5)=5

We move all terms to the left:

(2x+1)(x+5)-(5)=0

We multiply parentheses ..

(+2x^2+10x+x+5)-5=0

We get rid of parentheses

2x^2+10x+x+5-5=0

We add all the numbers together, and all the variables

2x^2+11x=0

a = 2; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·2·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*2}=\frac{-22}{4}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*2}=\frac{0}{4}
=0
$