x^2-12=4x+56-4(x+1)

Solution for x^2-12=4x+56-4(x+1) equation:

x^2-12=4x+56-4(x+1)

We move all terms to the left:

x^2-12-(4x+56-4(x+1))=0


We calculate terms in parentheses: -(4x+56-4(x+1)), so:

4x+56-4(x+1)

determiningTheFunctionDomain
4x-4(x+1)+56

We multiply parentheses

4x-4x-4+56

We add all the numbers together, and all the variables

52

Back to the equation:

-(52)


We add all the numbers together, and all the variables

x^2-64=0

a = 1; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·1·(-64)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*1}=\frac{16}{2}
=8
$