10-2(x-8)=4+3(x+7)

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Solution for 10-2(x-8)=4+3(x+7) equation: 



10-2(x-8)=4+3(x+7)

We move all terms to the left:

10-2(x-8)-(4+3(x+7))=0

We multiply parentheses

-2x-(4+3(x+7))+16+10=0



We calculate terms in parentheses: -(4+3(x+7)), so:

4+3(x+7)

determiningTheFunctionDomain
3(x+7)+4

We multiply parentheses

3x+21+4

We add all the numbers together, and all the variables

3x+25

Back to the equation:

-(3x+25)



We add all the numbers together, and all the variables

-2x-(3x+25)+26=0

We get rid of parentheses

-2x-3x-25+26=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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