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v-9/10v=5
We move all terms to the left:
v-9/10v-(5)=0
Domain of the equation: 10v!=0We multiply all the terms by the denominator
v!=0/10
v!=0
v∈R
v*10v-5*10v-9=0
Wy multiply elements
10v^2-50v-9=0
a = 10; b = -50; c = -9;
Δ = b2-4ac
Δ = -502-4·10·(-9)
Δ = 2860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2860}=\sqrt{4*715}=\sqrt{4}*\sqrt{715}=2\sqrt{715}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{715}}{2*10}=\frac{50-2\sqrt{715}}{20} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{715}}{2*10}=\frac{50+2\sqrt{715}}{20} $
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