3x-2(2x-5)=2(x+2)-8

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Solution for 3x-2(2x-5)=2(x+2)-8 equation: 



3x-2(2x-5)=2(x+2)-8

We move all terms to the left:

3x-2(2x-5)-(2(x+2)-8)=0

We multiply parentheses

3x-4x-(2(x+2)-8)+10=0



We calculate terms in parentheses: -(2(x+2)-8), so:

2(x+2)-8

We multiply parentheses

2x+4-8

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

-1x-(2x-4)+10=0

We get rid of parentheses

-1x-2x+4+10=0

We add all the numbers together, and all the variables

-3x+14=0

We move all terms containing x to the left, all other terms to the right

-3x=-14

x=-14/-3

x=4+2/3

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