-24b2+8b=0

Solution for -24b2+8b=0 equation:

-24b^2+8b=0

a = -24; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-24)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-24}=\frac{-16}{-48}
=1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-24}=\frac{0}{-48}
=0
$