u+4u+12=30(u-6)

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Solution for u+4u+12=30(u-6) equation: 



u+4u+12=30(u-6)

We move all terms to the left:

u+4u+12-(30(u-6))=0

We add all the numbers together, and all the variables

5u-(30(u-6))+12=0



We calculate terms in parentheses: -(30(u-6)), so:

30(u-6)

We multiply parentheses

30u-180

Back to the equation:

-(30u-180)



We get rid of parentheses

5u-30u+180+12=0

We add all the numbers together, and all the variables

-25u+192=0

We move all terms containing u to the left, all other terms to the right

-25u=-192

u=-192/-25

u=7+17/25

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