0.3(9y+3)+9=0.16(12-6y)

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Solution for 0.3(9y+3)+9=0.16(12-6y) equation: 



0.3(9y+3)+9=0.16(12-6y)

We move all terms to the left:

0.3(9y+3)+9-(0.16(12-6y))=0

We add all the numbers together, and all the variables

0.3(9y+3)-(0.16(-6y+12))+9=0

We multiply parentheses

2.7y-(0.16(-6y+12))+0.9+9=0



We calculate terms in parentheses: -(0.16(-6y+12)), so:

0.16(-6y+12)

We multiply parentheses

-0.96y+1.92

Back to the equation:

-(-0.96y+1.92)



We add all the numbers together, and all the variables

2.7y-(-0.96y+1.92)+9.9=0

We get rid of parentheses

2.7y+0.96y-1.92+9.9=0

We add all the numbers together, and all the variables

3.66y+7.98=0

We move all terms containing y to the left, all other terms to the right

3.66y=-7.98

y=-7.98/3.66

y=-2+0.66/3.66

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