2x-3(1x-4)=1x+2(3x-2)

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Solution for 2x-3(1x-4)=1x+2(3x-2) equation: 



2x-3(1x-4)=1x+2(3x-2)

We move all terms to the left:

2x-3(1x-4)-(1x+2(3x-2))=0

We add all the numbers together, and all the variables

2x-3(x-4)-(1x+2(3x-2))=0

We multiply parentheses

2x-3x-(1x+2(3x-2))+12=0



We calculate terms in parentheses: -(1x+2(3x-2)), so:

1x+2(3x-2)

We add all the numbers together, and all the variables

x+2(3x-2)

We multiply parentheses

x+6x-4

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We add all the numbers together, and all the variables

-1x-(7x-4)+12=0

We get rid of parentheses

-1x-7x+4+12=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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