t2-10t-54=0

Solution for t2-10t-54=0 equation:

t2-10t-54=0

We add all the numbers together, and all the variables

t^2-10t-54=0

a = 1; b = -10; c = -54;
Δ = b2-4ac
Δ = -102-4·1·(-54)
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{79}}{2*1}=\frac{10-2\sqrt{79}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{79}}{2*1}=\frac{10+2\sqrt{79}}{2}
$