3(4y-5)+14=2(2y+2)+17

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Solution for 3(4y-5)+14=2(2y+2)+17 equation: 



3(4y-5)+14=2(2y+2)+17

We move all terms to the left:

3(4y-5)+14-(2(2y+2)+17)=0

We multiply parentheses

12y-(2(2y+2)+17)-15+14=0



We calculate terms in parentheses: -(2(2y+2)+17), so:

2(2y+2)+17

We multiply parentheses

4y+4+17

We add all the numbers together, and all the variables

4y+21

Back to the equation:

-(4y+21)



We add all the numbers together, and all the variables

12y-(4y+21)-1=0

We get rid of parentheses

12y-4y-21-1=0

We add all the numbers together, and all the variables

8y-22=0

We move all terms containing y to the left, all other terms to the right

8y=22

y=22/8

y=2+3/4

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