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4(4x+3)=3(2x+5)
We move all terms to the left:
4(4x+3)-(3(2x+5))=0
We multiply parentheses
16x-(3(2x+5))+12=0
We calculate terms in parentheses: -(3(2x+5)), so:We get rid of parentheses
3(2x+5)
We multiply parentheses
6x+15
Back to the equation:
-(6x+15)
16x-6x-15+12=0
We add all the numbers together, and all the variables
10x-3=0
We move all terms containing x to the left, all other terms to the right
10x=3
x=3/10
x=3/10
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