t(5/6)=32

Solution for t(5/6)=32 equation:

t(5/6)=32

We move all terms to the left:

t(5/6)-(32)=0

We add all the numbers together, and all the variables

t(+5/6)-32=0

We multiply parentheses

5t^2-32=0

a = 5; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·5·(-32)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*5}=\frac{0-8\sqrt{10}}{10}
=-\frac{8\sqrt{10}}{10}
=-\frac{4\sqrt{10}}{5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*5}=\frac{0+8\sqrt{10}}{10}
=\frac{8\sqrt{10}}{10}
=\frac{4\sqrt{10}}{5}
$