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1/3x-7=6-5x
We move all terms to the left:
1/3x-7-(6-5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(-5x+6)-7=0
We get rid of parentheses
1/3x+5x-6-7=0
We multiply all the terms by the denominator
5x*3x-6*3x-7*3x+1=0
Wy multiply elements
15x^2-18x-21x+1=0
We add all the numbers together, and all the variables
15x^2-39x+1=0
a = 15; b = -39; c = +1;
Δ = b2-4ac
Δ = -392-4·15·1
Δ = 1461
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1461}}{2*15}=\frac{39-\sqrt{1461}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1461}}{2*15}=\frac{39+\sqrt{1461}}{30} $
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