(k-4)-7k=32-2(k+8)

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Solution for (k-4)-7k=32-2(k+8) equation: 



(k-4)-7k=32-2(k+8)

We move all terms to the left:

(k-4)-7k-(32-2(k+8))=0

We add all the numbers together, and all the variables

-7k+(k-4)-(32-2(k+8))=0

We get rid of parentheses

-7k+k-(32-2(k+8))-4=0



We calculate terms in parentheses: -(32-2(k+8)), so:

32-2(k+8)

determiningTheFunctionDomain
-2(k+8)+32

We multiply parentheses

-2k-16+32

We add all the numbers together, and all the variables

-2k+16

Back to the equation:

-(-2k+16)



We add all the numbers together, and all the variables

-6k-(-2k+16)-4=0

We get rid of parentheses

-6k+2k-16-4=0

We add all the numbers together, and all the variables

-4k-20=0

We move all terms containing k to the left, all other terms to the right

-4k=20

k=20/-4

k=-5

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