p2=2p+35p2=2p+35

Solution for p2=2p+35p2=2p+35 equation:

p2=2p+35p^2=2p+35

We move all terms to the left:

p2-(2p+35p^2)=0

We add all the numbers together, and all the variables

p^2-(2p+35p^2)=0

We get rid of parentheses

p^2-35p^2-2p=0

We add all the numbers together, and all the variables

-34p^2-2p=0

a = -34; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-34)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-34}=\frac{0}{-68}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-34}=\frac{4}{-68}
=-1/17
$